Base | Representation |
---|---|
bin | 100000101110010… |
… | …100110101110101 |
3 | 1102021001211212020 |
4 | 200232110311311 |
5 | 2111021434101 |
6 | 130251143353 |
7 | 16414356351 |
oct | 4056246565 |
9 | 1367054766 |
10 | 549014901 |
11 | 2619a5026 |
12 | 133a44b59 |
13 | 89986cb6 |
14 | 52cb4461 |
15 | 332eb136 |
hex | 20b94d75 |
549014901 has 4 divisors (see below), whose sum is σ = 732019872. Its totient is φ = 366009932.
The previous prime is 549014897. The next prime is 549014911. The reversal of 549014901 is 109410945.
549014901 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 549014901 - 22 = 549014897 is a prime.
It is an alternating number because its digits alternate between odd and even.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (549014911) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 91502481 + ... + 91502486.
It is an arithmetic number, because the mean of its divisors is an integer number (183004968).
Almost surely, 2549014901 is an apocalyptic number.
It is an amenable number.
549014901 is a deficient number, since it is larger than the sum of its proper divisors (183004971).
549014901 is a wasteful number, since it uses less digits than its factorization.
549014901 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 183004970.
The product of its (nonzero) digits is 6480, while the sum is 33.
The square root of 549014901 is about 23431.0670051536. The cubic root of 549014901 is about 818.8318191373.
The spelling of 549014901 in words is "five hundred forty-nine million, fourteen thousand, nine hundred one".
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