Base | Representation |
---|---|
bin | 1010001110110001… |
… | …10010010010111111 |
3 | 112011210101101100012 |
4 | 11013120302102333 |
5 | 42222104201403 |
6 | 2305010253435 |
7 | 253053505256 |
oct | 50730622277 |
9 | 15153341305 |
10 | 5492647103 |
11 | 2369502079 |
12 | 109358727b |
13 | 696c3ac58 |
14 | 3a16a179d |
15 | 22231aed8 |
hex | 1476324bf |
5492647103 has 4 divisors (see below), whose sum is σ = 5596282008. Its totient is φ = 5389012200.
The previous prime is 5492647087. The next prime is 5492647109. The reversal of 5492647103 is 3017462945.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 5492647103 - 24 = 5492647087 is a prime.
It is a super-4 number, since 4×54926471034 (a number of 40 digits) contains 4444 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5492647109) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 51817373 + ... + 51817478.
It is an arithmetic number, because the mean of its divisors is an integer number (1399070502).
Almost surely, 25492647103 is an apocalyptic number.
5492647103 is a gapful number since it is divisible by the number (53) formed by its first and last digit.
5492647103 is a deficient number, since it is larger than the sum of its proper divisors (103634905).
5492647103 is a wasteful number, since it uses less digits than its factorization.
5492647103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 103634904.
The product of its (nonzero) digits is 181440, while the sum is 41.
The square root of 5492647103 is about 74112.3950699207. The cubic root of 5492647103 is about 1764.3872020849.
The spelling of 5492647103 in words is "five billion, four hundred ninety-two million, six hundred forty-seven thousand, one hundred three".
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