Base | Representation |
---|---|
bin | 11000111111000110100000… |
… | …10010001000011110111111 |
3 | 21012112122220201210111100220 |
4 | 30133203100102020132333 |
5 | 24200203234303032303 |
6 | 312505130515152423 |
7 | 14400424166452323 |
oct | 1437432022103677 |
9 | 235478821714326 |
10 | 54944716064703 |
11 | 16563a178a3823 |
12 | 61b47a22a5713 |
13 | 2487359123c9a |
14 | d7d4a49ab983 |
15 | 654388b9b053 |
hex | 31f8d04887bf |
54944716064703 has 4 divisors (see below), whose sum is σ = 73259621419608. Its totient is φ = 36629810709800.
The previous prime is 54944716064699. The next prime is 54944716064717. The reversal of 54944716064703 is 30746061744945.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 54944716064703 - 22 = 54944716064699 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (54944716064743) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9157452677448 + ... + 9157452677453.
It is an arithmetic number, because the mean of its divisors is an integer number (18314905354902).
Almost surely, 254944716064703 is an apocalyptic number.
54944716064703 is a deficient number, since it is larger than the sum of its proper divisors (18314905354905).
54944716064703 is a wasteful number, since it uses less digits than its factorization.
54944716064703 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 18314905354904.
The product of its (nonzero) digits is 60963840, while the sum is 60.
The spelling of 54944716064703 in words is "fifty-four trillion, nine hundred forty-four billion, seven hundred sixteen million, sixty-four thousand, seven hundred three".
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