54949993 has 4 divisors (see below), whose sum is σ = 62800000. Its totient is φ = 47099988.

The previous prime is 54949991. The next prime is 54949997. The reversal of 54949993 is 39994945.

54949993 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 54949993 - 2¹ = 54949991 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 54949993.

It is not an unprimeable number, because it can be changed into a prime (54949991) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3924993 + ... + 3925006.

It is an arithmetic number, because the mean of its divisors is an integer number (15700000).

Almost surely, 2^54949993 is an apocalyptic number.

It is an amenable number.

54949993 is a deficient number, since it is larger than the sum of its proper divisors (7850007).

54949993 is an equidigital number, since it uses as much as digits as its factorization.

54949993 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7850006.

The product of its digits is 1574640, while the sum is 52.

The square root of 54949993 is about 7412.8262491441. The cubic root of 54949993 is about 380.1799540098.

The spelling of 54949993 in words is "fifty-four million, nine hundred forty-nine thousand, nine hundred ninety-three".