Base | Representation |
---|---|
bin | 100000110001000… |
… | …110110111000111 |
3 | 1102022102220002112 |
4 | 200301012313013 |
5 | 2111213302241 |
6 | 130314531235 |
7 | 16423514252 |
oct | 4061066707 |
9 | 1368386075 |
10 | 549744071 |
11 | 262352948 |
12 | 134136b1b |
13 | 89b80b66 |
14 | 53024099 |
15 | 333e21eb |
hex | 20c46dc7 |
549744071 has 2 divisors, whose sum is σ = 549744072. Its totient is φ = 549744070.
The previous prime is 549744061. The next prime is 549744077. The reversal of 549744071 is 170447945.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-549744071 is a prime.
It is a Chen prime.
It is equal to p28832666 and since 549744071 and 28832666 have the same sum of digits, it is a Honaker prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (549744077) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 274872035 + 274872036.
It is an arithmetic number, because the mean of its divisors is an integer number (274872036).
Almost surely, 2549744071 is an apocalyptic number.
549744071 is a deficient number, since it is larger than the sum of its proper divisors (1).
549744071 is an equidigital number, since it uses as much as digits as its factorization.
549744071 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 141120, while the sum is 41.
The square root of 549744071 is about 23446.6217396025. The cubic root of 549744071 is about 819.1941672029.
The spelling of 549744071 in words is "five hundred forty-nine million, seven hundred forty-four thousand, seventy-one".
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