Base | Representation |
---|---|
bin | 110011001110010000… |
… | …010110011000000001 |
3 | 12020222001012111012002 |
4 | 303032100112120001 |
5 | 1400120000000001 |
6 | 41133332513345 |
7 | 3654644200142 |
oct | 631620263001 |
9 | 166861174162 |
10 | 55000000001 |
11 | 21364080061 |
12 | a7ab47b855 |
13 | 52568cb5cb |
14 | 293a7d1ac9 |
15 | 166d7eb46b |
hex | cce416601 |
55000000001 has 2 divisors, whose sum is σ = 55000000002. Its totient is φ = 55000000000.
The previous prime is 54999999953. The next prime is 55000000021. The reversal of 55000000001 is 10000000055.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 42261491776 + 12738508225 = 205576^2 + 112865^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-55000000001 is a prime.
It is a super-2 number, since 2×550000000012 (a number of 22 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is a Curzon number.
It is not a weakly prime, because it can be changed into another prime (55000000021) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27500000000 + 27500000001.
It is an arithmetic number, because the mean of its divisors is an integer number (27500000001).
Almost surely, 255000000001 is an apocalyptic number.
It is an amenable number.
55000000001 is a deficient number, since it is larger than the sum of its proper divisors (1).
55000000001 is an equidigital number, since it uses as much as digits as its factorization.
55000000001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 25, while the sum is 11.
Adding to 55000000001 its reverse (10000000055), we get a palindrome (65000000056).
The spelling of 55000000001 in words is "fifty-five billion, one", and thus it is an aban number and an uban number.
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