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5500050150013 is a prime number
BaseRepresentation
bin101000000001001010010…
…0010010001001001111101
3201110210120221200201112121
41100002110202101021331
51210103100314300023
615410404350402541
71105236240622456
oct120022442211175
921423527621477
105500050150013
111830615a18451
12749b43800451
1330b8637207b3
141502bd50212d
159810795dd5d
hex5009489127d

5500050150013 has 2 divisors, whose sum is σ = 5500050150014. Its totient is φ = 5500050150012.

The previous prime is 5500050149981. The next prime is 5500050150043. The reversal of 5500050150013 is 3100510500055.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 5260770687769 + 239279462244 = 2293637^2 + 489162^2 .

It is a cyclic number.

It is not a de Polignac number, because 5500050150013 - 25 = 5500050149981 is a prime.

It is a super-3 number, since 3×55000501500133 (a number of 39 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 5500050150013.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5500050150043) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2750025075006 + 2750025075007.

It is an arithmetic number, because the mean of its divisors is an integer number (2750025075007).

Almost surely, 25500050150013 is an apocalyptic number.

It is an amenable number.

5500050150013 is a deficient number, since it is larger than the sum of its proper divisors (1).

5500050150013 is an equidigital number, since it uses as much as digits as its factorization.

5500050150013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1875, while the sum is 25.

Adding to 5500050150013 its reverse (3100510500055), we get a palindrome (8600560650068).

The spelling of 5500050150013 in words is "five trillion, five hundred billion, fifty million, one hundred fifty thousand, thirteen".