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550005105103 = 1515073630229
BaseRepresentation
bin10000000000011101101…
…10111110000111001111
31221120122210122020202021
420000032312332013033
533002402301330403
61100400250111011
754510432153646
oct10001666760717
91846583566667
10550005105103
111a228a5a8043
128a71771b467
133cb32c8736c
141c8984c235d
15e490b858bd
hex800edbe1cf

550005105103 has 4 divisors (see below), whose sum is σ = 550008886840. Its totient is φ = 550001323368.

The previous prime is 550005105079. The next prime is 550005105121. The reversal of 550005105103 is 301501500055.

550005105103 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 550005105103 - 213 = 550005096911 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (550005105173) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1663608 + ... + 1966621.

It is an arithmetic number, because the mean of its divisors is an integer number (137502221710).

Almost surely, 2550005105103 is an apocalyptic number.

550005105103 is a deficient number, since it is larger than the sum of its proper divisors (3781737).

550005105103 is a wasteful number, since it uses less digits than its factorization.

550005105103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3781736.

The product of its (nonzero) digits is 1875, while the sum is 25.

Adding to 550005105103 its reverse (301501500055), we get a palindrome (851506605158).

The spelling of 550005105103 in words is "five hundred fifty billion, five million, one hundred five thousand, one hundred three".

Divisors: 1 151507 3630229 550005105103