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5500183933 is a prime number
BaseRepresentation
bin1010001111101011…
…00010010101111101
3112012022120021221001
411013311202111331
542231021341213
62305440010301
7253204535446
oct50765422575
915168507831
105500183933
11237278a662
121096000991
1369867960a
143a26a42cd
15222d091dd
hex147d6257d

5500183933 has 2 divisors, whose sum is σ = 5500183934. Its totient is φ = 5500183932.

The previous prime is 5500183849. The next prime is 5500183937. The reversal of 5500183933 is 3393810055.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3167100729 + 2333083204 = 56277^2 + 48302^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-5500183933 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 5500183892 and 5500183901.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5500183937) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2750091966 + 2750091967.

It is an arithmetic number, because the mean of its divisors is an integer number (2750091967).

Almost surely, 25500183933 is an apocalyptic number.

It is an amenable number.

5500183933 is a deficient number, since it is larger than the sum of its proper divisors (1).

5500183933 is an equidigital number, since it uses as much as digits as its factorization.

5500183933 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 48600, while the sum is 37.

The square root of 5500183933 is about 74163.2249366221. The cubic root of 5500183933 is about 1765.1938446425.

Adding to 5500183933 its reverse (3393810055), we get a palindrome (8893993988).

The spelling of 5500183933 in words is "five billion, five hundred million, one hundred eighty-three thousand, nine hundred thirty-three".