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55002433441 = 99155501951
BaseRepresentation
bin110011001110011001…
…101000011110100001
312020222012210010020111
4303032121220132201
51400121110332231
641133501011321
73655003653544
oct631631503641
9166865703214
1055002433441
112136549236a
12a7b0253b41
135257271107
14293ac6685b
15166db2c4b1
hexcce6687a1

55002433441 has 4 divisors (see below), whose sum is σ = 55057936384. Its totient is φ = 54946930500.

The previous prime is 55002433417. The next prime is 55002433459. The reversal of 55002433441 is 14433420055.

55002433441 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 55002433441 - 27 = 55002433313 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (55002434441) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 27749985 + ... + 27751966.

It is an arithmetic number, because the mean of its divisors is an integer number (13764484096).

Almost surely, 255002433441 is an apocalyptic number.

It is an amenable number.

55002433441 is a deficient number, since it is larger than the sum of its proper divisors (55502943).

55002433441 is an equidigital number, since it uses as much as digits as its factorization.

55002433441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 55502942.

The product of its (nonzero) digits is 28800, while the sum is 31.

Adding to 55002433441 its reverse (14433420055), we get a palindrome (69435853496).

The spelling of 55002433441 in words is "fifty-five billion, two million, four hundred thirty-three thousand, four hundred forty-one".

Divisors: 1 991 55501951 55002433441