Base | Representation |
---|---|
bin | 11001000000111000110000… |
… | …11011101001100001001101 |
3 | 21012202112020121211011110210 |
4 | 30200130120123221201031 |
5 | 24202204400322423010 |
6 | 312553233332153033 |
7 | 14405025230021640 |
oct | 1440343033514115 |
9 | 235675217734423 |
10 | 55006056061005 |
11 | 16587a34706945 |
12 | 6204660a68779 |
13 | 249008338109a |
14 | d824433d3a57 |
15 | 655c78d8eb20 |
hex | 3207186e984d |
55006056061005 has 16 divisors (see below), whose sum is σ = 100582502511744. Its totient is φ = 25145625627840.
The previous prime is 55006056061003. The next prime is 55006056061043. The reversal of 55006056061005 is 50016065060055.
It is not a de Polignac number, because 55006056061005 - 21 = 55006056061003 is a prime.
It is a super-2 number, since 2×550060560610052 (a number of 28 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (55006056061003) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 261933600186 + ... + 261933600395.
It is an arithmetic number, because the mean of its divisors is an integer number (6286406406984).
Almost surely, 255006056061005 is an apocalyptic number.
It is an amenable number.
55006056061005 is a deficient number, since it is larger than the sum of its proper divisors (45576446450739).
55006056061005 is a wasteful number, since it uses less digits than its factorization.
55006056061005 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 523867200596.
The product of its (nonzero) digits is 135000, while the sum is 39.
The spelling of 55006056061005 in words is "fifty-five trillion, six billion, fifty-six million, sixty-one thousand, five".
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