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55006056061005 = 357523867200581
BaseRepresentation
bin11001000000111000110000…
…11011101001100001001101
321012202112020121211011110210
430200130120123221201031
524202204400322423010
6312553233332153033
714405025230021640
oct1440343033514115
9235675217734423
1055006056061005
1116587a34706945
126204660a68779
13249008338109a
14d824433d3a57
15655c78d8eb20
hex3207186e984d

55006056061005 has 16 divisors (see below), whose sum is σ = 100582502511744. Its totient is φ = 25145625627840.

The previous prime is 55006056061003. The next prime is 55006056061043. The reversal of 55006056061005 is 50016065060055.

It is not a de Polignac number, because 55006056061005 - 21 = 55006056061003 is a prime.

It is a super-2 number, since 2×550060560610052 (a number of 28 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (55006056061003) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 261933600186 + ... + 261933600395.

It is an arithmetic number, because the mean of its divisors is an integer number (6286406406984).

Almost surely, 255006056061005 is an apocalyptic number.

It is an amenable number.

55006056061005 is a deficient number, since it is larger than the sum of its proper divisors (45576446450739).

55006056061005 is a wasteful number, since it uses less digits than its factorization.

55006056061005 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 523867200596.

The product of its (nonzero) digits is 135000, while the sum is 39.

The spelling of 55006056061005 in words is "fifty-five trillion, six billion, fifty-six million, sixty-one thousand, five".

Divisors: 1 3 5 7 15 21 35 105 523867200581 1571601601743 2619336002905 3667070404067 7858008008715 11001211212201 18335352020335 55006056061005