Base | Representation |
---|---|
bin | 10000000000101001001… |
… | …00110001111100000011 |
3 | 1221120220111002012201212 |
4 | 20000110210301330003 |
5 | 33003101323444224 |
6 | 1100413553320335 |
7 | 54513005230511 |
oct | 10002444617403 |
9 | 1846814065655 |
10 | 550100999939 |
11 | 1a2329745277 |
12 | 8a7438660ab |
13 | 3cb49ac147a |
14 | 1c8a71254b1 |
15 | e4992c8d0e |
hex | 8014931f03 |
550100999939 has 2 divisors, whose sum is σ = 550100999940. Its totient is φ = 550100999938.
The previous prime is 550100999927. The next prime is 550101000013. The reversal of 550100999939 is 939999001055.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 550100999939 - 24 = 550100999923 is a prime.
It is a super-3 number, since 3×5501009999393 (a number of 36 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (550100999909) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 275050499969 + 275050499970.
It is an arithmetic number, because the mean of its divisors is an integer number (275050499970).
Almost surely, 2550100999939 is an apocalyptic number.
550100999939 is a deficient number, since it is larger than the sum of its proper divisors (1).
550100999939 is an equidigital number, since it uses as much as digits as its factorization.
550100999939 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4428675, while the sum is 59.
The spelling of 550100999939 in words is "five hundred fifty billion, one hundred million, nine hundred ninety-nine thousand, nine hundred thirty-nine".
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