Base | Representation |
---|---|
bin | 10000000000101001001… |
… | …00110001111101001101 |
3 | 1221120220111002012211121 |
4 | 20000110210301331031 |
5 | 33003101324000023 |
6 | 1100413553320541 |
7 | 54513005230645 |
oct | 10002444617515 |
9 | 1846814065747 |
10 | 550101000013 |
11 | 1a2329745334 |
12 | 8a743866151 |
13 | 3cb49ac1506 |
14 | 1c8a7125525 |
15 | e4992c8d5d |
hex | 8014931f4d |
550101000013 has 2 divisors, whose sum is σ = 550101000014. Its totient is φ = 550101000012.
The previous prime is 550100999939. The next prime is 550101000067. The reversal of 550101000013 is 310000101055.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 464800788169 + 85300211844 = 681763^2 + 292062^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-550101000013 is a prime.
It is a super-2 number, since 2×5501010000132 (a number of 24 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (550101000073) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 275050500006 + 275050500007.
It is an arithmetic number, because the mean of its divisors is an integer number (275050500007).
Almost surely, 2550101000013 is an apocalyptic number.
It is an amenable number.
550101000013 is a deficient number, since it is larger than the sum of its proper divisors (1).
550101000013 is an equidigital number, since it uses as much as digits as its factorization.
550101000013 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 75, while the sum is 16.
Adding to 550101000013 its reverse (310000101055), we get a palindrome (860101101068).
The spelling of 550101000013 in words is "five hundred fifty billion, one hundred one million, thirteen", and thus it is an aban number.
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