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55012720043 is a prime number
BaseRepresentation
bin110011001111000000…
…110111110110101011
312020222221010201210202
4303033000313312223
51400131224020133
641134505302415
73655160255621
oct631700676653
9166887121722
1055012720043
1121370278896
12a7b3794a0b
135259433268
14293c383511
15166e9b02e8
hexccf037dab

55012720043 has 2 divisors, whose sum is σ = 55012720044. Its totient is φ = 55012720042.

The previous prime is 55012720033. The next prime is 55012720051. The reversal of 55012720043 is 34002721055.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 55012720043 - 28 = 55012719787 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 55012719988 and 55012720015.

It is not a weakly prime, because it can be changed into another prime (55012720003) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27506360021 + 27506360022.

It is an arithmetic number, because the mean of its divisors is an integer number (27506360022).

Almost surely, 255012720043 is an apocalyptic number.

55012720043 is a deficient number, since it is larger than the sum of its proper divisors (1).

55012720043 is an equidigital number, since it uses as much as digits as its factorization.

55012720043 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 8400, while the sum is 29.

The spelling of 55012720043 in words is "fifty-five billion, twelve million, seven hundred twenty thousand, forty-three".