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55019413 is a prime number
BaseRepresentation
bin1101000111100…
…0011110010101
310211112021110001
43101320132111
5103041110123
65243131301
71235441311
oct321703625
9124467401
1055019413
1129069999
1216513b31
13b524c87
147442b41
154c6c0ad
hex3478795

55019413 has 2 divisors, whose sum is σ = 55019414. Its totient is φ = 55019412.

The previous prime is 55019401. The next prime is 55019423. The reversal of 55019413 is 31491055.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 40934404 + 14085009 = 6398^2 + 3753^2 .

It is a cyclic number.

It is not a de Polignac number, because 55019413 - 217 = 54888341 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (55019423) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27509706 + 27509707.

It is an arithmetic number, because the mean of its divisors is an integer number (27509707).

Almost surely, 255019413 is an apocalyptic number.

It is an amenable number.

55019413 is a deficient number, since it is larger than the sum of its proper divisors (1).

55019413 is an equidigital number, since it uses as much as digits as its factorization.

55019413 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2700, while the sum is 28.

The square root of 55019413 is about 7417.5071958172. The cubic root of 55019413 is about 380.3399842772.

The spelling of 55019413 in words is "fifty-five million, nineteen thousand, four hundred thirteen".