Base | Representation |
---|---|
bin | 110011001111100000… |
… | …111000111100100001 |
3 | 12021000111221010221111 |
4 | 303033200320330201 |
5 | 1400140401104441 |
6 | 41135405223321 |
7 | 3655321513342 |
oct | 631740707441 |
9 | 167014833844 |
10 | 55021113121 |
11 | 21374a90717 |
12 | a7b6561b41 |
13 | 525b0b1590 |
14 | 293d52a0c9 |
15 | 16705bc081 |
hex | ccf838f21 |
55021113121 has 16 divisors (see below), whose sum is σ = 63394623040. Its totient is φ = 47326835520.
The previous prime is 55021113089. The next prime is 55021113137. The reversal of 55021113121 is 12131112055.
55021113121 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 55021113121 - 25 = 55021113089 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 55021113092 and 55021113101.
It is not an unprimeable number, because it can be changed into a prime (55021113421) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1810815 + ... + 1840948.
It is an arithmetic number, because the mean of its divisors is an integer number (3962163940).
Almost surely, 255021113121 is an apocalyptic number.
It is an amenable number.
55021113121 is a deficient number, since it is larger than the sum of its proper divisors (8373509919).
55021113121 is a wasteful number, since it uses less digits than its factorization.
55021113121 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3651856.
The product of its (nonzero) digits is 300, while the sum is 22.
Adding to 55021113121 its reverse (12131112055), we get a palindrome (67152225176).
The spelling of 55021113121 in words is "fifty-five billion, twenty-one million, one hundred thirteen thousand, one hundred twenty-one".
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