Base | Representation |
---|---|
bin | 10000000000110110100… |
… | …00011010001000001100 |
3 | 1221121012022000111011121 |
4 | 20000123100122020030 |
5 | 33003314023200134 |
6 | 1100433040130324 |
7 | 54515536120126 |
oct | 10003320321014 |
9 | 1847168014147 |
10 | 550213100044 |
11 | 1a2386a50793 |
12 | 8a7753069a4 |
13 | 3cb670b06aa |
14 | 1c8b7d86216 |
15 | e4a406dab4 |
hex | 801b41a20c |
550213100044 has 6 divisors (see below), whose sum is σ = 962872925084. Its totient is φ = 275106550020.
The previous prime is 550213100039. The next prime is 550213100057. The reversal of 550213100044 is 440001312055.
It is a happy number.
It is a junction number, because it is equal to n+sod(n) for n = 550213099991 and 550213100018.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68776637502 + ... + 68776637509.
Almost surely, 2550213100044 is an apocalyptic number.
It is an amenable number.
550213100044 is a deficient number, since it is larger than the sum of its proper divisors (412659825040).
550213100044 is a wasteful number, since it uses less digits than its factorization.
550213100044 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 137553275015 (or 137553275013 counting only the distinct ones).
The product of its (nonzero) digits is 2400, while the sum is 25.
Adding to 550213100044 its reverse (440001312055), we get a palindrome (990214412099).
The spelling of 550213100044 in words is "five hundred fifty billion, two hundred thirteen million, one hundred thousand, forty-four".
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