Search a number
-
+
550213200377 is a prime number
BaseRepresentation
bin10000000000110110100…
…00110010100111111001
31221121012022012120210122
420000123100302213321
533003314034403002
61100433042223025
754515540015501
oct10003320624771
91847168176718
10550213200377
111a238700a105
128a775354a75
133cb67117269
141c8b7db0a01
15e4a408d6a2
hex801b4329f9

550213200377 has 2 divisors, whose sum is σ = 550213200378. Its totient is φ = 550213200376.

The previous prime is 550213200359. The next prime is 550213200413. The reversal of 550213200377 is 773002312055.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 541665088441 + 8548111936 = 735979^2 + 92456^2 .

It is a cyclic number.

It is not a de Polignac number, because 550213200377 - 222 = 550209006073 is a prime.

It is not a weakly prime, because it can be changed into another prime (550213206377) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 275106600188 + 275106600189.

It is an arithmetic number, because the mean of its divisors is an integer number (275106600189).

Almost surely, 2550213200377 is an apocalyptic number.

It is an amenable number.

550213200377 is a deficient number, since it is larger than the sum of its proper divisors (1).

550213200377 is an equidigital number, since it uses as much as digits as its factorization.

550213200377 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 44100, while the sum is 35.

The spelling of 550213200377 in words is "five hundred fifty billion, two hundred thirteen million, two hundred thousand, three hundred seventy-seven".