Base | Representation |
---|---|
bin | 11001000001011001010000… |
… | …10110011100110111110010 |
3 | 21012211012021112022122201011 |
4 | 30200230220112130313302 |
5 | 24203001113232044442 |
6 | 313005240500501134 |
7 | 14406213461415253 |
oct | 1440545026346762 |
9 | 235735245278634 |
10 | 55023503003122 |
11 | 16594377a92775 |
12 | 6207b0b9aa7aa |
13 | 2491903b40384 |
14 | d8321a5b6b2a |
15 | 65644a8ee117 |
hex | 320b2859cdf2 |
55023503003122 has 4 divisors (see below), whose sum is σ = 82535254504686. Its totient is φ = 27511751501560.
The previous prime is 55023503003033. The next prime is 55023503003171. The reversal of 55023503003122 is 22130030532055.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 29913472201041 + 25110030802081 = 5469321^2 + 5010991^2 .
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 13755875750779 + ... + 13755875750782.
Almost surely, 255023503003122 is an apocalyptic number.
55023503003122 is a deficient number, since it is larger than the sum of its proper divisors (27511751501564).
55023503003122 is a wasteful number, since it uses less digits than its factorization.
55023503003122 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 27511751501563.
The product of its (nonzero) digits is 27000, while the sum is 31.
Adding to 55023503003122 its reverse (22130030532055), we get a palindrome (77153533535177).
The spelling of 55023503003122 in words is "fifty-five trillion, twenty-three billion, five hundred three million, three thousand, one hundred twenty-two".
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