Base | Representation |
---|---|
bin | 1010000100000100011001… |
… | …00110111101010111010111 |
3 | 2220100121110212200210100111 |
4 | 11002002030212331113113 |
5 | 10400034300304011210 |
6 | 115022221244423451 |
7 | 4442561533560025 |
oct | 502021446752727 |
9 | 86317425623314 |
10 | 22130030532055 |
11 | 7062325341156 |
12 | 2594b46547b87 |
13 | c46b11b4cb24 |
14 | 567156283715 |
15 | 2859bd70888a |
hex | 14208c9bd5d7 |
22130030532055 has 8 divisors (see below), whose sum is σ = 26952395394672. Its totient is φ = 17439785254848.
The previous prime is 22130030532019. The next prime is 22130030532073. The reversal of 22130030532055 is 55023503003122.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 22130030532055 - 243 = 13333937509847 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 33029895982 + ... + 33029896651.
It is an arithmetic number, because the mean of its divisors is an integer number (3369049424334).
Almost surely, 222130030532055 is an apocalyptic number.
22130030532055 is a deficient number, since it is larger than the sum of its proper divisors (4822364862617).
22130030532055 is an equidigital number, since it uses as much as digits as its factorization.
22130030532055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 66059792705.
The product of its (nonzero) digits is 27000, while the sum is 31.
Adding to 22130030532055 its reverse (55023503003122), we get a palindrome (77153533535177).
The spelling of 22130030532055 in words is "twenty-two trillion, one hundred thirty billion, thirty million, five hundred thirty-two thousand, fifty-five".
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