Base | Representation |
---|---|
bin | 101000000010001110110… |
… | …1100101000000111100101 |
3 | 201111000112022210111101021 |
4 | 1100010131230220013211 |
5 | 1210122303421002401 |
6 | 15411424553131141 |
7 | 1105350252506233 |
oct | 120043554500745 |
9 | 21430468714337 |
10 | 5502351344101 |
11 | 1831596984647 |
12 | 74a4863b9ab1 |
13 | 30bb3c3c32c1 |
14 | 15045ada1953 |
15 | 981de9b92a1 |
hex | 5011db281e5 |
5502351344101 has 2 divisors, whose sum is σ = 5502351344102. Its totient is φ = 5502351344100.
The previous prime is 5502351344081. The next prime is 5502351344137. The reversal of 5502351344101 is 1014431532055.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2906595355876 + 2595755988225 = 1704874^2 + 1611135^2 .
It is a cyclic number.
It is not a de Polignac number, because 5502351344101 - 25 = 5502351344069 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5502351344141) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2751175672050 + 2751175672051.
It is an arithmetic number, because the mean of its divisors is an integer number (2751175672051).
Almost surely, 25502351344101 is an apocalyptic number.
It is an amenable number.
5502351344101 is a deficient number, since it is larger than the sum of its proper divisors (1).
5502351344101 is an equidigital number, since it uses as much as digits as its factorization.
5502351344101 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 36000, while the sum is 34.
Adding to 5502351344101 its reverse (1014431532055), we get a palindrome (6516782876156).
The spelling of 5502351344101 in words is "five trillion, five hundred two billion, three hundred fifty-one million, three hundred forty-four thousand, one hundred one".
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