Base | Representation |
---|---|
bin | 110011001111101100… |
… | …011000000010000011 |
3 | 12021000201121010010211 |
4 | 303033230120002003 |
5 | 1400142133432120 |
6 | 41135553534551 |
7 | 3655356223456 |
oct | 631754300203 |
9 | 167021533124 |
10 | 55024124035 |
11 | 21376757881 |
12 | a7b7574457 |
13 | 525b8c6b9a |
14 | 293dab149d |
15 | 16709b425a |
hex | ccfb18083 |
55024124035 has 4 divisors (see below), whose sum is σ = 66028948848. Its totient is φ = 44019299224.
The previous prime is 55024124017. The next prime is 55024124041. The reversal of 55024124035 is 53042142055.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 55024124035 - 217 = 55023992963 is a prime.
It is a super-4 number, since 4×550241240354 (a number of 44 digits) contains 4444 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 55024123988 and 55024124006.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5502412399 + ... + 5502412408.
It is an arithmetic number, because the mean of its divisors is an integer number (16507237212).
Almost surely, 255024124035 is an apocalyptic number.
55024124035 is a deficient number, since it is larger than the sum of its proper divisors (11004824813).
55024124035 is a wasteful number, since it uses less digits than its factorization.
55024124035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11004824812.
The product of its (nonzero) digits is 24000, while the sum is 31.
The spelling of 55024124035 in words is "fifty-five billion, twenty-four million, one hundred twenty-four thousand, thirty-five".
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