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55024124035 = 511004824807
BaseRepresentation
bin110011001111101100…
…011000000010000011
312021000201121010010211
4303033230120002003
51400142133432120
641135553534551
73655356223456
oct631754300203
9167021533124
1055024124035
1121376757881
12a7b7574457
13525b8c6b9a
14293dab149d
1516709b425a
hexccfb18083

55024124035 has 4 divisors (see below), whose sum is σ = 66028948848. Its totient is φ = 44019299224.

The previous prime is 55024124017. The next prime is 55024124041. The reversal of 55024124035 is 53042142055.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 55024124035 - 217 = 55023992963 is a prime.

It is a super-4 number, since 4×550241240354 (a number of 44 digits) contains 4444 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 55024123988 and 55024124006.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5502412399 + ... + 5502412408.

It is an arithmetic number, because the mean of its divisors is an integer number (16507237212).

Almost surely, 255024124035 is an apocalyptic number.

55024124035 is a deficient number, since it is larger than the sum of its proper divisors (11004824813).

55024124035 is a wasteful number, since it uses less digits than its factorization.

55024124035 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 11004824812.

The product of its (nonzero) digits is 24000, while the sum is 31.

The spelling of 55024124035 in words is "fifty-five billion, twenty-four million, one hundred twenty-four thousand, thirty-five".

Divisors: 1 5 11004824807 55024124035