Base | Representation |
---|---|
bin | 111110100011100010011111… |
… | …1110110011010100010000111 |
3 | 2200011020122100010200000021212 |
4 | 1331013010333312122202013 |
5 | 1034110132024400442021 |
6 | 5230133441245402035 |
7 | 223620455033246105 |
oct | 17507047766324207 |
9 | 2604218303600255 |
10 | 550242216421511 |
11 | 14a362460426409 |
12 | 51868764b6931b |
13 | 1a8048067193b3 |
14 | 99c3c18826c75 |
15 | 43930e1d7b85b |
hex | 1f4713fd9a887 |
550242216421511 has 2 divisors, whose sum is σ = 550242216421512. Its totient is φ = 550242216421510.
The previous prime is 550242216421507. The next prime is 550242216421571. The reversal of 550242216421511 is 115124612242055.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 550242216421511 - 22 = 550242216421507 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (550242216421571) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 275121108210755 + 275121108210756.
It is an arithmetic number, because the mean of its divisors is an integer number (275121108210756).
Almost surely, 2550242216421511 is an apocalyptic number.
550242216421511 is a deficient number, since it is larger than the sum of its proper divisors (1).
550242216421511 is an equidigital number, since it uses as much as digits as its factorization.
550242216421511 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 192000, while the sum is 41.
Adding to 550242216421511 its reverse (115124612242055), we get a palindrome (665366828663566).
The spelling of 550242216421511 in words is "five hundred fifty trillion, two hundred forty-two billion, two hundred sixteen million, four hundred twenty-one thousand, five hundred eleven".
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