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5502551204317 is a prime number
BaseRepresentation
bin101000000010010100110…
…0111000010000111011101
3201111001001020212110001111
41100010221213002013131
51210123211102014232
615411500452542021
71105355230342126
oct120045147020735
921431036773044
105502551204317
111831689781582
1274a521321911
1330bb7192ba9b
1415047974904d
15982022e7047
hex501299c21dd

5502551204317 has 2 divisors, whose sum is σ = 5502551204318. Its totient is φ = 5502551204316.

The previous prime is 5502551204309. The next prime is 5502551204341. The reversal of 5502551204317 is 7134021552055.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 5435211473316 + 67339731001 = 2331354^2 + 259499^2 .

It is a cyclic number.

It is not a de Polignac number, because 5502551204317 - 23 = 5502551204309 is a prime.

It is a super-2 number, since 2×55025512043172 (a number of 26 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 5502551204317.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5502551234317) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2751275602158 + 2751275602159.

It is an arithmetic number, because the mean of its divisors is an integer number (2751275602159).

Almost surely, 25502551204317 is an apocalyptic number.

It is an amenable number.

5502551204317 is a deficient number, since it is larger than the sum of its proper divisors (1).

5502551204317 is an equidigital number, since it uses as much as digits as its factorization.

5502551204317 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 210000, while the sum is 40.

The spelling of 5502551204317 in words is "five trillion, five hundred two billion, five hundred fifty-one million, two hundred four thousand, three hundred seventeen".