Base | Representation |
---|---|
bin | 11001000001100101100100… |
… | …11011011000110001010001 |
3 | 21012211211100022001112001000 |
4 | 30200302302123120301101 |
5 | 24203103133304121040 |
6 | 313012252520332213 |
7 | 14406536352401142 |
oct | 1440626233306121 |
9 | 235754308045030 |
10 | 55030114520145 |
11 | 16597160018326 |
12 | 6209256014069 |
13 | 2492418807c1b |
14 | d836866c9ac9 |
15 | 6566d607c130 |
hex | 320cb26d8c51 |
55030114520145 has 64 divisors (see below), whose sum is σ = 99219933849600. Its totient is φ = 28932897954240.
The previous prime is 55030114520113. The next prime is 55030114520179. The reversal of 55030114520145 is 54102541103055.
55030114520145 is a `hidden beast` number, since 5 + 5 + 0 + 3 + 0 + 114 + 520 + 14 + 5 = 666.
It is not a de Polignac number, because 55030114520145 - 25 = 55030114520113 is a prime.
It is a super-2 number, since 2×550301145201452 (a number of 28 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 89822466 + ... + 90433044.
It is an arithmetic number, because the mean of its divisors is an integer number (1550311466400).
Almost surely, 255030114520145 is an apocalyptic number.
It is an amenable number.
55030114520145 is a deficient number, since it is larger than the sum of its proper divisors (44189819329455).
55030114520145 is a wasteful number, since it uses less digits than its factorization.
55030114520145 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 620067 (or 620061 counting only the distinct ones).
The product of its (nonzero) digits is 60000, while the sum is 36.
The spelling of 55030114520145 in words is "fifty-five trillion, thirty billion, one hundred fourteen million, five hundred twenty thousand, one hundred forty-five".
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