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550332140053 = 5211056299693
BaseRepresentation
bin10000000001000100101…
…10100000101000010101
31221121111121000100100211
420000202112200220111
533004040011440203
61100452531405421
754521513002423
oct10004226405025
91847447010324
10550332140053
111a2438167263
128a7a9153871
133cb8595c677
141c8c9ad2113
15e4ae734c6d
hex80225a0a15

550332140053 has 4 divisors (see below), whose sum is σ = 551388440268. Its totient is φ = 549275839840.

The previous prime is 550332140011. The next prime is 550332140081. The reversal of 550332140053 is 350041233055.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 372566185924 + 177765954129 = 610382^2 + 421623^2 .

It is a cyclic number.

It is not a de Polignac number, because 550332140053 - 213 = 550332131861 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 550332139997 and 550332140024.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (550332141053) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 528149326 + ... + 528150367.

It is an arithmetic number, because the mean of its divisors is an integer number (137847110067).

Almost surely, 2550332140053 is an apocalyptic number.

It is an amenable number.

550332140053 is a deficient number, since it is larger than the sum of its proper divisors (1056300215).

550332140053 is a wasteful number, since it uses less digits than its factorization.

550332140053 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1056300214.

The product of its (nonzero) digits is 27000, while the sum is 31.

The spelling of 550332140053 in words is "five hundred fifty billion, three hundred thirty-two million, one hundred forty thousand, fifty-three".

Divisors: 1 521 1056299693 550332140053