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5503325404853 = 31193191935073
BaseRepresentation
bin101000000010101011111…
…0000010111111010110101
3201111010001012122220112102
41100011113300113322311
51210131302300423403
615412105350431445
71105413351053423
oct120052760277265
921433035586472
105503325404853
111831a467a0931
1274a6b8662585
1330bc6614a903
141505104ba113
159824a274b88
hex50157c17eb5

5503325404853 has 8 divisors (see below), whose sum is σ = 5683794014976. Its totient is φ = 5323040668800.

The previous prime is 5503325404847. The next prime is 5503325404867. The reversal of 5503325404853 is 3584045233055.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 5503325404853 - 26 = 5503325404789 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 5503325404798 and 5503325404807.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5503325404813) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 45907676 + ... + 46027397.

It is an arithmetic number, because the mean of its divisors is an integer number (710474251872).

Almost surely, 25503325404853 is an apocalyptic number.

It is an amenable number.

5503325404853 is a deficient number, since it is larger than the sum of its proper divisors (180468610123).

5503325404853 is a wasteful number, since it uses less digits than its factorization.

5503325404853 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 91937035.

The product of its (nonzero) digits is 4320000, while the sum is 47.

The spelling of 5503325404853 in words is "five trillion, five hundred three billion, three hundred twenty-five million, four hundred four thousand, eight hundred fifty-three".

Divisors: 1 31 1931 59861 91935073 2849987263 177526625963 5503325404853