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550343460353 = 717751316343
BaseRepresentation
bin10000000001000110000…
…01101100011000000001
31221121112101022110220012
420000203001230120001
533004100411212403
61100454014154305
754522011141261
oct10004301543001
91847471273805
10550343460353
111a2443599385
128a7b0ab2995
133cb880c417b
141c8cb3db7a1
15e4b071ded8
hex802306c601

550343460353 has 4 divisors (see below), whose sum is σ = 558094776768. Its totient is φ = 542592143940.

The previous prime is 550343460313. The next prime is 550343460367. The reversal of 550343460353 is 353064343055.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 550343460353 - 216 = 550343394817 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 550343460353.

It is not an unprimeable number, because it can be changed into a prime (550343460313) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3875658101 + ... + 3875658242.

It is an arithmetic number, because the mean of its divisors is an integer number (139523694192).

Almost surely, 2550343460353 is an apocalyptic number.

It is an amenable number.

550343460353 is a deficient number, since it is larger than the sum of its proper divisors (7751316415).

550343460353 is an equidigital number, since it uses as much as digits as its factorization.

550343460353 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7751316414.

The product of its (nonzero) digits is 972000, while the sum is 41.

The spelling of 550343460353 in words is "five hundred fifty billion, three hundred forty-three million, four hundred sixty thousand, three hundred fifty-three".

Divisors: 1 71 7751316343 550343460353