Base | Representation |
---|---|
bin | 101000000010110001001… |
… | …1111100101001010010001 |
3 | 201111010111202122022222121 |
4 | 1100011202133211022101 |
5 | 1210132134410131032 |
6 | 15412135303534241 |
7 | 1105420666224004 |
oct | 120054237451221 |
9 | 21433452568877 |
10 | 5503505552017 |
11 | 1832029454090 |
12 | 74a748a5a381 |
13 | 30bc94573775 |
14 | 15052a3b153b |
15 | 9825aeaba97 |
hex | 501627e5291 |
5503505552017 has 4 divisors (see below), whose sum is σ = 6003824238576. Its totient is φ = 5003186865460.
The previous prime is 5503505552011. The next prime is 5503505552029. The reversal of 5503505552017 is 7102555053055.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 5503505552017 - 23 = 5503505552009 is a prime.
It is a super-2 number, since 2×55035055520172 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (5503505552011) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 250159343263 + ... + 250159343284.
It is an arithmetic number, because the mean of its divisors is an integer number (1500956059644).
Almost surely, 25503505552017 is an apocalyptic number.
It is an amenable number.
5503505552017 is a deficient number, since it is larger than the sum of its proper divisors (500318686559).
5503505552017 is a wasteful number, since it uses less digits than its factorization.
5503505552017 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 500318686558.
The product of its (nonzero) digits is 656250, while the sum is 43.
The spelling of 5503505552017 in words is "five trillion, five hundred three billion, five hundred five million, five hundred fifty-two thousand, seventeen".
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