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5503505552017 = 11500318686547
BaseRepresentation
bin101000000010110001001…
…1111100101001010010001
3201111010111202122022222121
41100011202133211022101
51210132134410131032
615412135303534241
71105420666224004
oct120054237451221
921433452568877
105503505552017
111832029454090
1274a748a5a381
1330bc94573775
1415052a3b153b
159825aeaba97
hex501627e5291

5503505552017 has 4 divisors (see below), whose sum is σ = 6003824238576. Its totient is φ = 5003186865460.

The previous prime is 5503505552011. The next prime is 5503505552029. The reversal of 5503505552017 is 7102555053055.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 5503505552017 - 23 = 5503505552009 is a prime.

It is a super-2 number, since 2×55035055520172 (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (5503505552011) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 250159343263 + ... + 250159343284.

It is an arithmetic number, because the mean of its divisors is an integer number (1500956059644).

Almost surely, 25503505552017 is an apocalyptic number.

It is an amenable number.

5503505552017 is a deficient number, since it is larger than the sum of its proper divisors (500318686559).

5503505552017 is a wasteful number, since it uses less digits than its factorization.

5503505552017 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 500318686558.

The product of its (nonzero) digits is 656250, while the sum is 43.

The spelling of 5503505552017 in words is "five trillion, five hundred three billion, five hundred five million, five hundred fifty-two thousand, seventeen".

Divisors: 1 11 500318686547 5503505552017