Base | Representation |
---|---|
bin | 101000000010110010100… |
… | …1001101011111100101111 |
3 | 201111010121212112212002202 |
4 | 1100011211021223330233 |
5 | 1210132232314104203 |
6 | 15412143535412115 |
7 | 1105422050236451 |
oct | 120054511537457 |
9 | 21433555485082 |
10 | 5503550144303 |
11 | 1832051640a12 |
12 | 74a75b98403b |
13 | 30bca0887633 |
14 | 15053229c2d1 |
15 | 9825ed69388 |
hex | 5016526bf2f |
5503550144303 has 4 divisors (see below), whose sum is σ = 5505206346888. Its totient is φ = 5501893941720.
The previous prime is 5503550144219. The next prime is 5503550144317. The reversal of 5503550144303 is 3034410553055.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5503550144303 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5503550141303) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 828096308 + ... + 828102953.
It is an arithmetic number, because the mean of its divisors is an integer number (1376301586722).
Almost surely, 25503550144303 is an apocalyptic number.
5503550144303 is a deficient number, since it is larger than the sum of its proper divisors (1656202585).
5503550144303 is a wasteful number, since it uses less digits than its factorization.
5503550144303 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1656202584.
The product of its (nonzero) digits is 270000, while the sum is 38.
Adding to 5503550144303 its reverse (3034410553055), we get a palindrome (8537960697358).
The spelling of 5503550144303 in words is "five trillion, five hundred three billion, five hundred fifty million, one hundred forty-four thousand, three hundred three".
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