Base | Representation |
---|---|
bin | 11001000001110111111011… |
… | …10101111000100101011111 |
3 | 21012212202210010022010021222 |
4 | 30200323331311320211133 |
5 | 24203233324220120444 |
6 | 313021002451043555 |
7 | 14410335521103455 |
oct | 1440737565704537 |
9 | 235782703263258 |
10 | 55039969691999 |
11 | 165a0358002856 |
12 | 620b1465a05bb |
13 | 24933294b7566 |
14 | d83d3d50c9d5 |
15 | 656ab137ceee |
hex | 320efdd7895f |
55039969691999 has 4 divisors (see below), whose sum is σ = 55282436519064. Its totient is φ = 54797502864936.
The previous prime is 55039969691981. The next prime is 55039969692053. The reversal of 55039969691999 is 99919696993055.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 55039969691999 - 28 = 55039969691743 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (55039969691599) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 121233413192 + ... + 121233413645.
It is an arithmetic number, because the mean of its divisors is an integer number (13820609129766).
Almost surely, 255039969691999 is an apocalyptic number.
55039969691999 is a deficient number, since it is larger than the sum of its proper divisors (242466827065).
55039969691999 is a wasteful number, since it uses less digits than its factorization.
55039969691999 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 242466827064.
The product of its (nonzero) digits is 12914016300, while the sum is 89.
The spelling of 55039969691999 in words is "fifty-five trillion, thirty-nine billion, nine hundred sixty-nine million, six hundred ninety-one thousand, nine hundred ninety-nine".
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