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55042040341 = 366911500151
BaseRepresentation
bin110011010000110000…
…101110001000010101
312021001222022100200201
4303100300232020111
51400211230242331
641141433540501
73655664423551
oct632060561025
9167058270621
1055042040341
1121385884642
12a801574731
13526252aa52
142942216861
151672352a61
hexcd0c2e215

55042040341 has 4 divisors (see below), whose sum is σ = 55043577184. Its totient is φ = 55040503500.

The previous prime is 55042040311. The next prime is 55042040351. The reversal of 55042040341 is 14304024055.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 55042040341 - 223 = 55033651733 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (55042040311) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 713385 + ... + 786766.

It is an arithmetic number, because the mean of its divisors is an integer number (13760894296).

Almost surely, 255042040341 is an apocalyptic number.

It is an amenable number.

55042040341 is a deficient number, since it is larger than the sum of its proper divisors (1536843).

55042040341 is a wasteful number, since it uses less digits than its factorization.

55042040341 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1536842.

The product of its (nonzero) digits is 9600, while the sum is 28.

Adding to 55042040341 its reverse (14304024055), we get a palindrome (69346064396).

The spelling of 55042040341 in words is "fifty-five billion, forty-two million, forty thousand, three hundred forty-one".

Divisors: 1 36691 1500151 55042040341