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55042243413 = 318347414471
BaseRepresentation
bin110011010000110001…
…011111101101010101
312021001222200200020220
4303100301133231111
51400211303242123
641141442144553
73655666230603
oct632061375525
9167058620226
1055042243413
1121385a03173
12a801652159
13526259c301
14294226a873
151672392ce3
hexcd0c5fb55

55042243413 has 4 divisors (see below), whose sum is σ = 73389657888. Its totient is φ = 36694828940.

The previous prime is 55042243393. The next prime is 55042243429. The reversal of 55042243413 is 31434224055.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-55042243413 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (55042243433) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9173707233 + ... + 9173707238.

It is an arithmetic number, because the mean of its divisors is an integer number (18347414472).

Almost surely, 255042243413 is an apocalyptic number.

It is an amenable number.

55042243413 is a deficient number, since it is larger than the sum of its proper divisors (18347414475).

55042243413 is a wasteful number, since it uses less digits than its factorization.

55042243413 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 18347414474.

The product of its (nonzero) digits is 57600, while the sum is 33.

Adding to 55042243413 its reverse (31434224055), we get a palindrome (86476467468).

The spelling of 55042243413 in words is "fifty-five billion, forty-two million, two hundred forty-three thousand, four hundred thirteen".

Divisors: 1 3 18347414471 55042243413