Base | Representation |
---|---|
bin | 10000000001001111111… |
… | …00101110010000110011 |
3 | 1221121202010201010121011 |
4 | 20000213330232100303 |
5 | 33004233031342233 |
6 | 1100510124211351 |
7 | 54524033113303 |
oct | 10004774562063 |
9 | 1847663633534 |
10 | 550426043443 |
11 | 1a2486174271 |
12 | 8a814699b57 |
13 | 3cb9c24a1c3 |
14 | 1c8d8377603 |
15 | e4b7ad30cd |
hex | 8027f2e433 |
550426043443 has 2 divisors, whose sum is σ = 550426043444. Its totient is φ = 550426043442.
The previous prime is 550426043441. The next prime is 550426043471. The reversal of 550426043443 is 344340624055.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 550426043443 - 21 = 550426043441 is a prime.
Together with 550426043441, it forms a pair of twin primes.
It is a junction number, because it is equal to n+sod(n) for n = 550426043396 and 550426043405.
It is not a weakly prime, because it can be changed into another prime (550426043441) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 275213021721 + 275213021722.
It is an arithmetic number, because the mean of its divisors is an integer number (275213021722).
Almost surely, 2550426043443 is an apocalyptic number.
550426043443 is a deficient number, since it is larger than the sum of its proper divisors (1).
550426043443 is an equidigital number, since it uses as much as digits as its factorization.
550426043443 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 691200, while the sum is 40.
Adding to 550426043443 its reverse (344340624055), we get a palindrome (894766667498).
The spelling of 550426043443 in words is "five hundred fifty billion, four hundred twenty-six million, forty-three thousand, four hundred forty-three".
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