Base | Representation |
---|---|
bin | 101000000011001101011… |
… | …0110101011101001111001 |
3 | 201111012221122220202220101 |
4 | 1100012122312223221321 |
5 | 1210141103442211100 |
6 | 15412413202555401 |
7 | 1105453300431016 |
oct | 120063266535171 |
9 | 21435848822811 |
10 | 5504451132025 |
11 | 183247418836a |
12 | 74a971668b61 |
13 | 30c0b5438771 |
14 | 1505b9bd470d |
15 | 982b3edd86a |
hex | 5019adaba79 |
5504451132025 has 12 divisors (see below), whose sum is σ = 7060882142700. Its totient is φ = 4251713977280.
The previous prime is 5504451131873. The next prime is 5504451132077. The reversal of 5504451132025 is 5202311544055.
It can be written as a sum of positive squares in 6 ways, for example, as 835463637369 + 4668987494656 = 914037^2 + 2160784^2 .
It is not a de Polignac number, because 5504451132025 - 217 = 5504451000953 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 3796172470 + ... + 3796173919.
It is an arithmetic number, because the mean of its divisors is an integer number (588406845225).
Almost surely, 25504451132025 is an apocalyptic number.
It is an amenable number.
5504451132025 is a deficient number, since it is larger than the sum of its proper divisors (1556431010675).
5504451132025 is a wasteful number, since it uses less digits than its factorization.
5504451132025 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7592346428 (or 7592346423 counting only the distinct ones).
The product of its (nonzero) digits is 120000, while the sum is 37.
The spelling of 5504451132025 in words is "five trillion, five hundred four billion, four hundred fifty-one million, one hundred thirty-two thousand, twenty-five".
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