Base | Representation |
---|---|
bin | 10000000001010100100… |
… | …10110111000111110011 |
3 | 1221121211212202201110201 |
4 | 20000222102313013303 |
5 | 33004323120320311 |
6 | 1100514051540031 |
7 | 54525021465316 |
oct | 10005222670763 |
9 | 1847755681421 |
10 | 550465401331 |
11 | 1a24a640644a |
12 | 8a8258ba617 |
13 | 3cba744a6b1 |
14 | 1c8dd6a097d |
15 | e4bb2a99c1 |
hex | 802a4b71f3 |
550465401331 has 2 divisors, whose sum is σ = 550465401332. Its totient is φ = 550465401330.
The previous prime is 550465401319. The next prime is 550465401377. The reversal of 550465401331 is 133104564055.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 550465401331 - 27 = 550465401203 is a prime.
It is a super-2 number, since 2×5504654013312 (a number of 24 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (550465401131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 275232700665 + 275232700666.
It is an arithmetic number, because the mean of its divisors is an integer number (275232700666).
Almost surely, 2550465401331 is an apocalyptic number.
550465401331 is a deficient number, since it is larger than the sum of its proper divisors (1).
550465401331 is an equidigital number, since it uses as much as digits as its factorization.
550465401331 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 108000, while the sum is 37.
Adding to 550465401331 its reverse (133104564055), we get a palindrome (683569965386).
The spelling of 550465401331 in words is "five hundred fifty billion, four hundred sixty-five million, four hundred one thousand, three hundred thirty-one".
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