Base | Representation |
---|---|
bin | 10000000001010100100… |
… | …10110111001000100001 |
3 | 1221121211212202201112102 |
4 | 20000222102313020201 |
5 | 33004323120321002 |
6 | 1100514051540145 |
7 | 54525021465413 |
oct | 10005222671041 |
9 | 1847755681472 |
10 | 550465401377 |
11 | 1a24a6406491 |
12 | 8a8258ba655 |
13 | 3cba744a718 |
14 | 1c8dd6a09b3 |
15 | e4bb2a9a02 |
hex | 802a4b7221 |
550465401377 has 2 divisors, whose sum is σ = 550465401378. Its totient is φ = 550465401376.
The previous prime is 550465401331. The next prime is 550465401407. The reversal of 550465401377 is 773104564055.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 384295847056 + 166169554321 = 619916^2 + 407639^2 .
It is a cyclic number.
It is not a de Polignac number, because 550465401377 - 228 = 550196965921 is a prime.
It is a super-2 number, since 2×5504654013772 (a number of 24 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (550465401877) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 275232700688 + 275232700689.
It is an arithmetic number, because the mean of its divisors is an integer number (275232700689).
Almost surely, 2550465401377 is an apocalyptic number.
It is an amenable number.
550465401377 is a deficient number, since it is larger than the sum of its proper divisors (1).
550465401377 is an equidigital number, since it uses as much as digits as its factorization.
550465401377 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1764000, while the sum is 47.
The spelling of 550465401377 in words is "five hundred fifty billion, four hundred sixty-five million, four hundred one thousand, three hundred seventy-seven".
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