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5504773442293 is a prime number
BaseRepresentation
bin101000000011010111000…
…0100001100101011110101
3201111020210010101211110201
41100012232010030223311
51210142234000123133
615412505155120501
71105464263141056
oct120065604145365
921436703354421
105504773442293
11183261a10a894
1274aa415a3131
1330c1371483b8
1415060a93472d
15982d2457d7d
hex501ae10caf5

5504773442293 has 2 divisors, whose sum is σ = 5504773442294. Its totient is φ = 5504773442292.

The previous prime is 5504773442243. The next prime is 5504773442309. The reversal of 5504773442293 is 3922443774055.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3293506299204 + 2211267143089 = 1814802^2 + 1487033^2 .

It is a cyclic number.

It is not a de Polignac number, because 5504773442293 - 213 = 5504773434101 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5504773442213) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2752386721146 + 2752386721147.

It is an arithmetic number, because the mean of its divisors is an integer number (2752386721147).

Almost surely, 25504773442293 is an apocalyptic number.

It is an amenable number.

5504773442293 is a deficient number, since it is larger than the sum of its proper divisors (1).

5504773442293 is an equidigital number, since it uses as much as digits as its factorization.

5504773442293 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 25401600, while the sum is 55.

The spelling of 5504773442293 in words is "five trillion, five hundred four billion, seven hundred seventy-three million, four hundred forty-two thousand, two hundred ninety-three".