Search a number
-
+
55050101011 = 488171127683
BaseRepresentation
bin110011010001001111…
…011110000100010011
312021002112110212212001
4303101033132010103
51400220311213021
641142322414431
73656123065213
oct632117360423
9167075425761
1055050101011
112138a38a754
12a804201417
1352640c0989
142943314243
151672de6091
hexcd13de113

55050101011 has 4 divisors (see below), whose sum is σ = 55051277512. Its totient is φ = 55048924512.

The previous prime is 55050101009. The next prime is 55050101017. The reversal of 55050101011 is 11010105055.

It is a happy number.

55050101011 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 55050101011 - 21 = 55050101009 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 55050101011.

It is not an unprimeable number, because it can be changed into a prime (55050101017) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 515025 + ... + 612658.

It is an arithmetic number, because the mean of its divisors is an integer number (13762819378).

Almost surely, 255050101011 is an apocalyptic number.

55050101011 is a deficient number, since it is larger than the sum of its proper divisors (1176501).

55050101011 is a wasteful number, since it uses less digits than its factorization.

55050101011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1176500.

The product of its (nonzero) digits is 125, while the sum is 19.

Adding to 55050101011 its reverse (11010105055), we get a palindrome (66060206066).

The spelling of 55050101011 in words is "fifty-five billion, fifty million, one hundred one thousand, eleven".

Divisors: 1 48817 1127683 55050101011