Base | Representation |
---|---|
bin | 101000000011011111011… |
… | …0110010000100010110001 |
3 | 201111021111202012111001211 |
4 | 1100012332312100202301 |
5 | 1210143323040011003 |
6 | 15412553134000121 |
7 | 1105504252302160 |
oct | 120067666204261 |
9 | 21437452174054 |
10 | 5505055000753 |
11 | 1832754038930 |
12 | 74aabb946041 |
13 | 30c18058a239 |
14 | 1506360a73d7 |
15 | 982ec02296d |
hex | 501bed908b1 |
5505055000753 has 16 divisors (see below), whose sum is σ = 6863624498304. Its totient is φ = 4289541183360.
The previous prime is 5505055000727. The next prime is 5505055000789. The reversal of 5505055000753 is 3570005505055.
It is a happy number.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5505055000753 is a prime.
It is a super-3 number, since 3×55050550007533 (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not an unprimeable number, because it can be changed into a prime (5505055004753) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2096151 + ... + 3924787.
It is an arithmetic number, because the mean of its divisors is an integer number (428976531144).
Almost surely, 25505055000753 is an apocalyptic number.
It is an amenable number.
5505055000753 is a deficient number, since it is larger than the sum of its proper divisors (1358569497551).
5505055000753 is a wasteful number, since it uses less digits than its factorization.
5505055000753 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1867752.
The product of its (nonzero) digits is 328125, while the sum is 40.
The spelling of 5505055000753 in words is "five trillion, five hundred five billion, fifty-five million, seven hundred fifty-three", and thus it is an aban number.
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