Base | Representation |
---|---|
bin | 10000000001011010000… |
… | …10111010111011111101 |
3 | 1221121222002121112102222 |
4 | 20000231002322323331 |
5 | 33004421424214201 |
6 | 1100522421055125 |
7 | 54526122001142 |
oct | 10005502727375 |
9 | 1847862545388 |
10 | 550511554301 |
11 | 1a251a4698a5 |
12 | 8a8392574a5 |
13 | 3cbb3b89a47 |
14 | 1c9058763c9 |
15 | e4c037491b |
hex | 802d0baefd |
550511554301 has 2 divisors, whose sum is σ = 550511554302. Its totient is φ = 550511554300.
The previous prime is 550511554267. The next prime is 550511554361. The reversal of 550511554301 is 103455115055.
550511554301 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 531142152025 + 19369402276 = 728795^2 + 139174^2 .
It is a cyclic number.
It is not a de Polignac number, because 550511554301 - 230 = 549437812477 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (550511554361) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 275255777150 + 275255777151.
It is an arithmetic number, because the mean of its divisors is an integer number (275255777151).
Almost surely, 2550511554301 is an apocalyptic number.
It is an amenable number.
550511554301 is a deficient number, since it is larger than the sum of its proper divisors (1).
550511554301 is an equidigital number, since it uses as much as digits as its factorization.
550511554301 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 37500, while the sum is 35.
Adding to 550511554301 its reverse (103455115055), we get a palindrome (653966669356).
The spelling of 550511554301 in words is "five hundred fifty billion, five hundred eleven million, five hundred fifty-four thousand, three hundred one".
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