Base | Representation |
---|---|
bin | 110011010001011100… |
… | …011111010100111011 |
3 | 12021002202220021122122 |
4 | 303101130133110323 |
5 | 1400222144422133 |
6 | 41142523511455 |
7 | 3656164101563 |
oct | 632134372473 |
9 | 167082807578 |
10 | 55053514043 |
11 | 21391300a40 |
12 | a80538858b |
13 | 5264a17318 |
14 | 2943961da3 |
15 | 167336c498 |
hex | cd171f53b |
55053514043 has 4 divisors (see below), whose sum is σ = 60058378968. Its totient is φ = 50048649120.
The previous prime is 55053514037. The next prime is 55053514057. The reversal of 55053514043 is 34041535055.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 55053514043 - 28 = 55053513787 is a prime.
It is a super-3 number, since 3×550535140433 (a number of 33 digits) contains 333 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 55053513994 and 55053514012.
It is not an unprimeable number, because it can be changed into a prime (55053514063) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2502432446 + ... + 2502432467.
It is an arithmetic number, because the mean of its divisors is an integer number (15014594742).
Almost surely, 255053514043 is an apocalyptic number.
55053514043 is a deficient number, since it is larger than the sum of its proper divisors (5004864925).
55053514043 is a wasteful number, since it uses less digits than its factorization.
55053514043 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5004864924.
The product of its (nonzero) digits is 90000, while the sum is 35.
The spelling of 55053514043 in words is "fifty-five billion, fifty-three million, five hundred fourteen thousand, forty-three".
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