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55054425331 = 271203152861
BaseRepresentation
bin110011010001011111…
…111101110011110011
312021002211121120201001
4303101133331303303
51400222413102311
641142555222431
73656204615443
oct632137756363
9167084546631
1055054425331
1121391873674
12a805747a17
135264c76049
142943b1c123
15167349c4c1
hexcd17fdcf3

55054425331 has 4 divisors (see below), whose sum is σ = 55257578464. Its totient is φ = 54851272200.

The previous prime is 55054425329. The next prime is 55054425337. The reversal of 55054425331 is 13352445055.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 13352445055 = 52670489011.

It is a cyclic number.

It is not a de Polignac number, because 55054425331 - 21 = 55054425329 is a prime.

It is a super-2 number, since 2×550544253312 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (55054425337) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 101576160 + ... + 101576701.

It is an arithmetic number, because the mean of its divisors is an integer number (13814394616).

Almost surely, 255054425331 is an apocalyptic number.

55054425331 is a deficient number, since it is larger than the sum of its proper divisors (203153133).

55054425331 is a wasteful number, since it uses less digits than its factorization.

55054425331 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 203153132.

The product of its (nonzero) digits is 180000, while the sum is 37.

The spelling of 55054425331 in words is "fifty-five billion, fifty-four million, four hundred twenty-five thousand, three hundred thirty-one".

Divisors: 1 271 203152861 55054425331