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55055000554949 is a prime number
BaseRepresentation
bin11001000010010011111011…
…10000000100110111000101
321012221012120122112001222202
430201021331300010313011
524204010120120224244
6313031530150404245
714411410144244363
oct1441117560046705
9235835518461882
1055055000554949
11165a677059463a
126212040360685
13249488354b2c5
14d84967888633
15657190c3c04e
hex32127dc04dc5

55055000554949 has 2 divisors, whose sum is σ = 55055000554950. Its totient is φ = 55055000554948.

The previous prime is 55055000554933. The next prime is 55055000555033. The reversal of 55055000554949 is 94945500055055.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 40554060394849 + 14500940160100 = 6368207^2 + 3808010^2 .

It is a cyclic number.

It is not a de Polignac number, because 55055000554949 - 24 = 55055000554933 is a prime.

It is a super-3 number, since 3×550550005549493 (a number of 42 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 55055000554894 and 55055000554903.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (55055000554249) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27527500277474 + 27527500277475.

It is an arithmetic number, because the mean of its divisors is an integer number (27527500277475).

Almost surely, 255055000554949 is an apocalyptic number.

It is an amenable number.

55055000554949 is a deficient number, since it is larger than the sum of its proper divisors (1).

55055000554949 is an equidigital number, since it uses as much as digits as its factorization.

55055000554949 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 20250000, while the sum is 56.

The spelling of 55055000554949 in words is "fifty-five trillion, fifty-five billion, five hundred fifty-four thousand, nine hundred forty-nine".