Base | Representation |
---|---|
bin | 11001000010010101111110… |
… | …10100011011111000111111 |
3 | 21012221022102022110102122212 |
4 | 30201022333110123320333 |
5 | 24204014343223334003 |
6 | 313032231244331035 |
7 | 14411446332441014 |
oct | 1441127724337077 |
9 | 235838368412585 |
10 | 55056100605503 |
11 | 165a7185533928 |
12 | 62122a8843a7b |
13 | 24949ca418caa |
14 | d84a2d9db70b |
15 | 6572075d2dd8 |
hex | 3212bf51be3f |
55056100605503 has 2 divisors, whose sum is σ = 55056100605504. Its totient is φ = 55056100605502.
The previous prime is 55056100605461. The next prime is 55056100605559. The reversal of 55056100605503 is 30550600165055.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 55056100605503 - 230 = 55055026863679 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (55056100605563) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27528050302751 + 27528050302752.
It is an arithmetic number, because the mean of its divisors is an integer number (27528050302752).
Almost surely, 255056100605503 is an apocalyptic number.
55056100605503 is a deficient number, since it is larger than the sum of its proper divisors (1).
55056100605503 is an equidigital number, since it uses as much as digits as its factorization.
55056100605503 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 337500, while the sum is 41.
The spelling of 55056100605503 in words is "fifty-five trillion, fifty-six billion, one hundred million, six hundred five thousand, five hundred three".
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