Base | Representation |
---|---|
bin | 101000000011111101011… |
… | …0001001110001011101001 |
3 | 201111101002210212122122122 |
4 | 1100013322301032023221 |
5 | 1210202402420011241 |
6 | 15413241005201025 |
7 | 1105541210310461 |
oct | 120077261161351 |
9 | 21441083778578 |
10 | 5506060313321 |
11 | 183311a560067 |
12 | 74b140560175 |
13 | 30c2b0937549 |
14 | 1506cd7d8ba1 |
15 | 9835a40304b |
hex | 501fac4e2e9 |
5506060313321 has 2 divisors, whose sum is σ = 5506060313322. Its totient is φ = 5506060313320.
The previous prime is 5506060313291. The next prime is 5506060313323. The reversal of 5506060313321 is 1233130606055.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 5478033870400 + 28026442921 = 2340520^2 + 167411^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5506060313321 is a prime.
Together with 5506060313323, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (5506060313323) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2753030156660 + 2753030156661.
It is an arithmetic number, because the mean of its divisors is an integer number (2753030156661).
Almost surely, 25506060313321 is an apocalyptic number.
It is an amenable number.
5506060313321 is a deficient number, since it is larger than the sum of its proper divisors (1).
5506060313321 is an equidigital number, since it uses as much as digits as its factorization.
5506060313321 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 48600, while the sum is 35.
Adding to 5506060313321 its reverse (1233130606055), we get a palindrome (6739190919376).
The spelling of 5506060313321 in words is "five trillion, five hundred six billion, sixty million, three hundred thirteen thousand, three hundred twenty-one".
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