Base | Representation |
---|---|
bin | 11001000011000010011111… |
… | …10101011000111111111001 |
3 | 21020000121002220101110112202 |
4 | 30201201033311120333321 |
5 | 24204412314444444433 |
6 | 313051222551315545 |
7 | 14413253514104663 |
oct | 1441411765307771 |
9 | 236017086343482 |
10 | 55079999999993 |
11 | 1660632a081721 |
12 | 6216a5867bbb5 |
13 | 249703891c037 |
14 | d85c59b29533 |
15 | 657b5584eee8 |
hex | 32184fd58ff9 |
55079999999993 has 2 divisors, whose sum is σ = 55079999999994. Its totient is φ = 55079999999992.
The previous prime is 55079999999891. The next prime is 55080000000029. The reversal of 55079999999993 is 39999999997055.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 49959903605824 + 5120096394169 = 7068232^2 + 2262763^2 .
It is a cyclic number.
It is not a de Polignac number, because 55079999999993 - 224 = 55079983222777 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 55079999999893 and 55079999999902.
It is not a weakly prime, because it can be changed into another prime (55079999999293) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27539999999996 + 27539999999997.
It is an arithmetic number, because the mean of its divisors is an integer number (27539999999997).
Almost surely, 255079999999993 is an apocalyptic number.
It is an amenable number.
55079999999993 is a deficient number, since it is larger than the sum of its proper divisors (1).
55079999999993 is an equidigital number, since it uses as much as digits as its factorization.
55079999999993 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 203395756725, while the sum is 101.
The spelling of 55079999999993 in words is "fifty-five trillion, seventy-nine billion, nine hundred ninety-nine million, nine hundred ninety-nine thousand, nine hundred ninety-three".
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