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55079999999993 is a prime number
BaseRepresentation
bin11001000011000010011111…
…10101011000111111111001
321020000121002220101110112202
430201201033311120333321
524204412314444444433
6313051222551315545
714413253514104663
oct1441411765307771
9236017086343482
1055079999999993
111660632a081721
126216a5867bbb5
13249703891c037
14d85c59b29533
15657b5584eee8
hex32184fd58ff9

55079999999993 has 2 divisors, whose sum is σ = 55079999999994. Its totient is φ = 55079999999992.

The previous prime is 55079999999891. The next prime is 55080000000029. The reversal of 55079999999993 is 39999999997055.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 49959903605824 + 5120096394169 = 7068232^2 + 2262763^2 .

It is a cyclic number.

It is not a de Polignac number, because 55079999999993 - 224 = 55079983222777 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 55079999999893 and 55079999999902.

It is not a weakly prime, because it can be changed into another prime (55079999999293) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27539999999996 + 27539999999997.

It is an arithmetic number, because the mean of its divisors is an integer number (27539999999997).

Almost surely, 255079999999993 is an apocalyptic number.

It is an amenable number.

55079999999993 is a deficient number, since it is larger than the sum of its proper divisors (1).

55079999999993 is an equidigital number, since it uses as much as digits as its factorization.

55079999999993 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 203395756725, while the sum is 101.

The spelling of 55079999999993 in words is "fifty-five trillion, seventy-nine billion, nine hundred ninety-nine million, nine hundred ninety-nine thousand, nine hundred ninety-three".