Base | Representation |
---|---|
bin | 11001000011101000101011… |
… | …10000110010001111111011 |
3 | 21020002120000121210100012202 |
4 | 30201310111300302033323 |
5 | 24210231311120110101 |
6 | 313104453121300415 |
7 | 14414610524651153 |
oct | 1441642560621773 |
9 | 236076017710182 |
10 | 55100500550651 |
11 | 16613a9a103876 |
12 | 621aa1a19470b |
13 | 2498c54c1259a |
14 | d86c426ab763 |
15 | 6584554e236b |
hex | 321d15c323fb |
55100500550651 has 4 divisors (see below), whose sum is σ = 55100862152952. Its totient is φ = 55100138948352.
The previous prime is 55100500550639. The next prime is 55100500550671. The reversal of 55100500550651 is 15605500500155.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-55100500550651 is a prime.
It is a super-3 number, since 3×551005005506513 (a number of 42 digits) contains 333 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (55100500550621) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 180572486 + ... + 180877371.
It is an arithmetic number, because the mean of its divisors is an integer number (13775215538238).
Almost surely, 255100500550651 is an apocalyptic number.
55100500550651 is a deficient number, since it is larger than the sum of its proper divisors (361602301).
55100500550651 is a wasteful number, since it uses less digits than its factorization.
55100500550651 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 361602300.
The product of its (nonzero) digits is 93750, while the sum is 38.
The spelling of 55100500550651 in words is "fifty-five trillion, one hundred billion, five hundred million, five hundred fifty thousand, six hundred fifty-one".
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