Base | Representation |
---|---|
bin | 11001000011101010101110… |
… | …11110110011000000110111 |
3 | 21020002122212110111020201112 |
4 | 30201311113132303000313 |
5 | 24210241040400201242 |
6 | 313105154345345235 |
7 | 14414650043513345 |
oct | 1441652736630067 |
9 | 236078773436645 |
10 | 55101603131447 |
11 | 16614505521074 |
12 | 621b08749821b |
13 | 249909c487b62 |
14 | d86d08cbc995 |
15 | 6584bc1d7c82 |
hex | 321d577b3037 |
55101603131447 has 4 divisors (see below), whose sum is σ = 55103803963416. Its totient is φ = 55099402299480.
The previous prime is 55101603131383. The next prime is 55101603131503. The reversal of 55101603131447 is 74413130610155.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 55101603131447 - 26 = 55101603131383 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (55101602131447) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1100378429 + ... + 1100428502.
It is an arithmetic number, because the mean of its divisors is an integer number (13775950990854).
Almost surely, 255101603131447 is an apocalyptic number.
55101603131447 is a deficient number, since it is larger than the sum of its proper divisors (2200831969).
55101603131447 is a wasteful number, since it uses less digits than its factorization.
55101603131447 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2200831968.
The product of its (nonzero) digits is 151200, while the sum is 41.
The spelling of 55101603131447 in words is "fifty-five trillion, one hundred one billion, six hundred three million, one hundred thirty-one thousand, four hundred forty-seven".
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