Base | Representation |
---|---|
bin | 110011010100011011… |
… | …101001110011100111 |
3 | 12021020021012020222111 |
4 | 303110123221303213 |
5 | 1400323012021341 |
6 | 41151513541451 |
7 | 3660343045135 |
oct | 632433516347 |
9 | 167207166874 |
10 | 55103626471 |
11 | 21407619173 |
12 | a81a114887 |
13 | 527221194a |
14 | 294a488755 |
15 | 167796a681 |
hex | cd46e9ce7 |
55103626471 has 2 divisors, whose sum is σ = 55103626472. Its totient is φ = 55103626470.
The previous prime is 55103626453. The next prime is 55103626477. The reversal of 55103626471 is 17462630155.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 55103626471 - 25 = 55103626439 is a prime.
It is a super-3 number, since 3×551036264713 (a number of 33 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (55103626477) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27551813235 + 27551813236.
It is an arithmetic number, because the mean of its divisors is an integer number (27551813236).
Almost surely, 255103626471 is an apocalyptic number.
55103626471 is a deficient number, since it is larger than the sum of its proper divisors (1).
55103626471 is an equidigital number, since it uses as much as digits as its factorization.
55103626471 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 151200, while the sum is 40.
The spelling of 55103626471 in words is "fifty-five billion, one hundred three million, six hundred twenty-six thousand, four hundred seventy-one".
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